Text Exercises

9.54 ventureH0 µ = 10 H1 µ > 10 consequence train take =0.01 take a chance honour 10 audition mean1.4 std difference4.45 std error0.752 n35 t sort t (14.44) =(14.44 - 10)/[4.45/?35= 5.9028 results: After the test the test stats is > than the critical measure so reject H0, record shows µ > 10 9.56 guessworkH0 p = 0.5 H1 p > 0.5 Significance level level =10% decimate if nada speculation if p measure out < 0.1 well-tried Hypothesis test proportion vs. supposition range watching none value 0.6330.5 38/6030/60 37.9830 6060 n 0.0645 std error 2.06 z .0197 p value results: because the p value is less than 0.1.1 the hypothesis is rejected so the evidence shows the level of significance of 10% is bias that the hit will show heads. 9.62 Hypothesis H0 p = 0.95 H1 p < 0.95 Significance levellevel =2.50% Reject if null hypothesis if p-value < 0.025 tested Hypothesis test proportion vs. hypothesis value Observatio nValue 0.970.95 485/ cholecalciferol 475/500 485475 X 500500 N 0.0097std error 2.05 Z 0.

0201p value results: the p value is < 0.025 so the null hypothesis is rejected. The evidence does settle that 9.64 Hypothesis H0 µ = 250 H1 µ > 250 significance level = 5%level =5% reject the null hypothesis if p value < 0.05 Tested Hypothesis test mean vs. hypothesis value hypothesis value 250 sample mean 275.66 std aberrancy78.11 std error 15.622 n25 df24 t1.64 p value 0.0568 results: Because the p value is < 0.05 the null hypothesis is not rejected. The evidence is insufficient to conclude the 5% significance level from the sample prove a violation of the guideline that the bonny persevering shou! ld pay no...If you want to get a rich essay, localize it on our website: OrderEssay.net

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